Respuesta :
Answer:
The answer to your question is letter C.
Explanation:
Reaction
Potassium hydroxide = KOH
Barium chloride = BaCl₂
Potassium chloride = KCl
Barium hydroxide = Ba(OH)₂
KOH + BaCl₂ ⇒ KCl + Ba(OH)₂
Reactant Elements Products
1 K 1
1 Ba 1
2 Cl 1
1 H 2
1 O 2
The reaction is unbalanced
2KOH + BaCl₂ ⇒ 2KCl + Ba(OH)₂
Reactant Elements Products
2 K 2
1 Ba 1
2 Cl 2
2 H 2
2 O 2
Now, the reaction is balanced
Answer: C.
2KOH + BaCl2 => 2KCl + Ba(OH)2
Explanation:
There are 2 atoms of O and H in Ba(OH)2 in the product so to balance we put 2 on KOH. Then balance K by adding 2 in KCl to have equal number of atoms for K and Cl in both the reactant and product side. Barium have 1 atom on the reactant and in the product.