Respuesta :
Answer:
527 Hz
Solution:
As per the question:
Beat frequency of the player, [tex]\Delta f = 4\ beats/s[/tex]
Frequency of the tuning fork, f = 523 Hz
Now,
The initial frequency can be calculated as:
[tex]\Delta f = f - f_{i}[/tex]
[tex]f_{i} = f \pm \Delta f[/tex]
when
[tex]f_{i} = f + \Delta f = 523 + 4 = 527 Hz[/tex]
when
[tex]f_{i} = f - \Delta f = 523 - 4 = 519 Hz[/tex]
But we know that as the length of the flute increases the frequency decreases
Hence, the initial frequency must be 527 Hz
Answer:
527 Hz
Explanation:
given,
flute beat = 4 beats/s
frequency of the tuning fork = 523 Hz
to find her initial frequency.
we know
[tex]f_{beat}=|f_1-f_2|[/tex]
[tex]4=|f_1-f_2|[/tex]
f₁ - f₂ = ±4
f₁ = 523 ± 4 Hz
now,
f₁ = 527 Hz (or) 519 Hz
when flute length increase the frequency decreases.
hence, initial frequency is equal to 527 Hz
