A rectangle that is 8 centimeters long has an area of 100 square centimeters. A similar rectangle has an area of 16 square centimeters. What is the width of the smaller rectangle

Respuesta :

Answer:

The width of the smaller rectangle is 5 centimeters

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the smaller rectangle

y ----> the area of the larger rectangle

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]x=16\ cm^2\\y=100\ cm^2[/tex]

substitute

[tex]z^{2}=\frac{16}{100}[/tex]

square root both sides

[tex]z=\frac{4}{10}[/tex]

step 2

Find the width of the larger rectangle

we know that the area is equal to

[tex]A=LW[/tex]

we have

[tex]A=100\ cm^2\\L=8\ cm[/tex]

substitute

[tex]100=8W\\W=12.5\ cm[/tex]

step 3

Find the width of the smaller rectangle

To find out the width of the smaller rectangle, multiply the width of the larger rectangle by the scale factor

so

[tex]12.5(\frac{4}{10})=5\ cm[/tex]