Answer:
c. Satellite 1 has a shorter period and faster speed than satellite 2.
Explanation:
The period of an object in a circular orbit is given by:
[tex]T=\frac{2\pi r}{v}(1)[/tex]
Here r is the radius of the circular orbit and v is the speed of the object. So, we have [tex]r_1<r_2[/tex], according to (1) the period is proportional to the radius, thus [tex]T_1<T_2[/tex]. In other hand the period is inversely proportional to the speed, so [tex]v_1>v_2[/tex]
