Answer:
Explanation:
given,
time taken to complete the each orbit = 144 minutes
t = 144 x 60 = 8640 s
mass of the earth = 5.98 x 10²⁴ Kg
radius of earth,R = 6.38 x 10⁶ m
Using Kepler's 3rd law
[tex]T^2 = (\dfrac{4\pi^2}{GM_e})r^3[/tex]
[tex] r = (\dfrac{T^2GM_e}{4\pi^2})^{1/3}[/tex]
[tex] r = (\dfrac{8640^2\times 6.67 \times 10^{-11}\times 5.98\times 10^{24}}{4\pi^2})^{1/3}[/tex]
r = 9.1 x 10⁶ m
the altitude of the satellite
H = r - R
H = 9.1 x 10⁶ - 6.38 x 10⁶
H = 2.72 x 10⁶ m
