Answer:
A = 25,500
B = 0.82
Step-by-step explanation:
The problem statement tells you the initial value of the car is 25,500, so that will be the value of V(0).
V(0) = A·B^0 = A
25,500 = A . . . . . . use the given value for V(0)
__
The problem statement tells you the value is 18% less after the first year, so is 1 -0.18 = 0.82 times the initial value.
V(1) = 25,500·B^1 = 25,500·B . . . . value after the first year
25,500·0.82 = 25,500·B . . . . substituting the given information
0.82 = B . . . . . . divide by 25,500
In summary, ...
_____
For these exponential growth/decay problems, you will find that A is always the initial value, and B is always (1+percentage change). Here the percentage change is -18%, so the value of B is 1-0.18 = 0.82.
