The correct answer is C) Ga₂Se₃
Why?
The simplest way to find the ionic character of the bond is to look at the electronegativity difference between the atoms involved in the bonding.
Let's look at each compound individually:
A) NaCl: [tex]ED=3-0.9=2.1[/tex]
B) NaF: [tex]ED=4-0.9=3.1[/tex]
C) Ga₂Se₃: [tex]ED=2.4-1.6=0.8[/tex]
D) ZnO: [tex]ED= 3.5-1.6=1.9[/tex]
E) Na₃PO₄: (assuming that oxygen is holding the negative charge) [tex]ED=3.5-0.9=2.6[/tex]
From all these compounds the one with the smallest electronegativity difference is Ga₂Se₃ so it is the least ionic in nature.
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The compound that has been least ionic is [tex]\rm \bold{Ga_2Se_3}[/tex]. The correct option is C.
Ionic compounds have been formed with the electrostatic interaction between the oppositely charged ions. The ionic bond has been formed by the transfer of electrons.
The ionic strength of the compound can be assessed by the difference in the electronegativity of the atoms involved in the bond.
The difference in electronegativity of the following compounds has been as follows:
A. NaCl
Difference = 3 - 0.9
Difference = 2.1
B. NaF
Difference = 4- 0.9
Difference = 3.1
C. [tex]\rm Ga_2Se_3[/tex]
Difference = 2.4 - 1.6
Difference = 0.8
D. ZnO
Difference = 3.5 - 1.6
Difference = 1.9
E. [tex]\rm Na_3PO_4[/tex]
Difference = 3.5 - 0.9
Difference = 2.6
The ionic compound with the least difference in electronegativity has been termed to be the least ionic in nature.
The smallest electronegativity difference has been observed in [tex]\rm Ga_2Se_3[/tex]. Thus the compound that has been least ionic is [tex]\rm \bold{Ga_2Se_3}[/tex]. The correct option is C.
For more information about the ionic strength of the compound, refer to the link:
https://brainly.com/question/14095804
