The new pressure is 2 Kpa
Solution:
At constant temperature, the pressure of a sample of gas is inversely proportional to its volume
Therefore,
[tex]\text{ pressure of a sample of gas} \propto \frac{1}{\text{volume}}[/tex]
Let "p" be the pressure of sample gas
Let "v" be the volume
Then we get,
[tex]p \propto \frac{1}{v}\\\\p = k \times \frac{1}{v}\\\\p = \frac{k}{v} ---------- eqn 1[/tex]
Where, "k" is the constant of proportionality
I have some oxygen in a 2.28 liter container with a pressure of 5 kPa
Substitute v = 2.28 and p = 5 in eqn 1
[tex]5 = \frac{k}{2.28}\\\\k = 5 \times 2.28\\\\k = 11.4[/tex]
I move all of it to a 5.7 liter container at the same temperature
Substitute k = 11.4 and v = 5.7 in eqn 1
[tex]p = \frac{11.4}{5.7}\\\\p = 2[/tex]
Thus new pressure is 2 kPa
