All of the 4th grade teachers and students from Cambridge went on a field trip to an art museum. Tickets were $5.50 per teacher and $3.00 for each student. This group paid $29.00 in total. The next month, the same group visited a science museum where the tickets were $22.00 for teachers and $11.50 for students. The group paid $113.00 in total. Find the number of teachers and students on the field trips.

Respuesta :

Answer:

Students= 6

Teachers= 2

Step-by-step explanation:

Given: Art museum trip:

           Cost of ticket= $5.5 per teacher and $3 per student.

           Total amount paid= $29.

           Science trip:

           Cost of ticket= $22 per teacher and $11.5 per student.

           Total amount paid= $113.

Lets assume number of teacher be "x" and number of students be "y".

Now, forming an equation for cost of each trip.

we know, total cost= [tex]cost\ of \ each\ ticket \times numbers\ of\ tickets[/tex]

∴Art museum trip, [tex]5.5x+3y= 29[/tex] ---- 1st equation

Science museum trip, [tex]22x+11.5y= 113[/tex] ---- 2nd equation

Next using elimination method to find number teacher and students

[tex]5.5x+3y= 29\\22x+11.5y= 113[/tex]

Multiplying both side of 1st equation by 4

∴ [tex]22x+12y= 116\\22x+11.5y= 113[/tex]

changing sign of 2nd equation on both side and solving it.

∴ [tex]0.5y= 3[/tex]

Dividing both side by 0.5

[tex]y= \frac{3}{0.5}= 6[/tex]

Hence, number of students on field trip was 6.

Subtituting the value of y in 1st equation to find the number of teachers in field trip.

[tex]5.5x+3y= 29[/tex]

[tex]5.5x+3\times 6= 29[/tex]

[tex]5.5x+18= 29[/tex]

Subtracting both side by 18

⇒ [tex]5.5x= 11[/tex]

Dividing both side by 5.5

⇒ [tex]x= \frac{11}{5.5}= 2[/tex]

Hence, there were 2 teachers on field trips.