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PART ONE
The arm of a crane at a construction site is
15.0 m long, and it makes an angle of 18.8◦
with the horizontal. Assume that the maximum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane withstand if the maximum load the crane can
handle is 553 N?
Answer in units of N · m.

PART TWO
What is the maximum load for this crane at
an angle of 27.0◦ with the horizontal?
Answer in units of N.

Respuesta :

MathPhys

Explanation:

Torque is the perpendicular component of the force times the distance.

τ = F⊥ r

Part One

τ = (553 N cos 18.8°) (15.0 m)

τ ≈ 7850 Nm

Part Two

7850 Nm = (F cos 27.0°) (15.0 m)

F ≈ 588 N

lhmarianateixeira

In this exercise we have to use the knowledge of torque, in this way it can be written as:

[tex]F = 588 N\\ [/tex]

Knowing that torque is the perpendicular component of the force times the distance, will have:

[tex]T = (553 N cos 18.8) (15.0 m)\\ T = 7850 Nm\\ 7850 Nm = (F cos 27.0) (15.0 m)[/tex]

See more about torque at brainly.com/question/6855614

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