Part one : The force exerted by the hammer claws on the nail is of 460.5 N.
Part two: The force exerted by the surface on the point of contact with the hammer head is of 431.7 N.
Given data:
The magnitude of horizontal force is, F = 62.5 N.
As per the given diagram, there are four forces on the hammer:
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Applied force 62.5 N in the +x direction, 30 cm from the ground
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Reaction force Rᵧ in the +y direction, at the point of contact
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Reaction force Rₓ in the +x direction, at the point of contact
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Reaction force F at 31° from the vertical, 4.75 cm to the left of the point of contact
Part One
To find F, sum the moments about the point of contact:
∑τ = Iα
(62.5 N) (30 cm) − (F cos 31°) (4.75 cm) = 0
F = 460.5 N
Thus, we can conclude that the force exerted by the hammer claws on the nail is of 460.5 N.
Part Two
To find Rₓ and Rᵧ, sum the forces in the x and y directions.
∑Fₓ = ma
62.5 N − F sin 31° + Rₓ = 0
Rₓ = 174.7 N
∑Fᵧ = ma
-F cos 31° + Rᵧ = 0
Rᵧ = 394.7 N
The force exerted by the surface on the point of contact with the hammer head is due to the net reaction force at point of contact.
Then, the net reaction force at the point of contact is:
[tex]R_{net}=\sqrt{R^{2}_{x}+R^{2}_{y}}\\\\R_{net}=\sqrt{174.7^{2}+394.7^{2}}\\\\R_{net} =431.7 \;\rm N[/tex]
Thus, we can conclude that the force exerted by the surface on the
point of contact with the hammer head is of 431.7 N.
Learn more about the reaction force here:
https://brainly.com/question/24098950
