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After three half-lives, a sample contains 20 grams of parent isotopes. How many grams of the parent isotope were present to start?

Respuesta :

The amount of a decaying substance in any time t (at) is calculated by the equation, 
                                           at = (a1) x (1/2)^h

where a1 is the original amount and h is the number of half-lives.

Substituting the given values with a1 as the unknown,
                              20 g = (a1) x (1/2)^3    ; a1 = 160 g

Thuss, there were 160 grams of the isotope at the beginning. 
 


Hom3workmachin3

Answer:

160 grams

Explanation:

Since the sample went through 3 half-lives we have to think about how it would have come to 20 grams of parent isotopes.

We know it cannot be 40, since 40/2 = 20, which is only one half-life.

We also know it can't be 80, since 80/2 = 40 and 40/2 = 20, which is only 2 half-lives.

So we are stuck with 2 answers, 320 and 160.

Since 320 takes 4 half-lives to get to 20 grams (320/2 = 160, 160/2 = 80, 80/2 = 40, 40/2 = 20), we know it cannot be the answer, so we move on to 160.

Let's see.

160/2 = 80, 80/2 = 40, 40/2 = 20

Exactly 3 half-lives!

Clearly the answer to your question of how many grams of the parent isotope was present to start if 20 parent isotopes remained after 3 half-lives is 160!

Have a magnificent day!

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