Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 9.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.

Respuesta :

Answer: The number of electrons in the given amount of silver are [tex]2.36\times 10^{24}[/tex]

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of silver = 9.0 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of silver}=\frac{9.0g}{107.87g/mol}=0.0834mol[/tex]

We are given:

Number of electrons in one atom of silver = 47

According to mole concept:

1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of particles

So, 0.0834 moles of silver contains [tex](47\times 0.0834\times 6.022\times 10^{23})=2.36\times 10^{24}[/tex] number of electrons

Hence, the number of electrons in the given amount of silver are [tex]2.36\times 10^{24}[/tex]