Answer:
1/376,992
Step-by-step explanation:
Assuming that the order at which the numbers are picked does not matter, the number of possible combinations of selecting 5 balls out of 36 is:
[tex]n=\frac{36!}{(36-5)!5!}=\frac{36*35*34*33*32}{5*4*3*2*1}=376,992[/tex]
Since each event can only happen once, the probability of getting all five balls right is:
[tex]P = \frac{1}{376,992}[/tex]