Answer: 0.0078 kg
Explanation:
The answer can be found using the Radioactive Half Life Formula:
[tex]A=A_{o}.2^{\frac{-t}{h}}[/tex]
Where:
[tex]A[/tex] is the final amount of phosphorus-32
[tex]A_{o}=1 kg[/tex] is the initial amount of phosphorus-32
[tex]t=100.1 days[/tex] is the time elapsed
[tex]h=14.3 days[/tex] is the half life of phosphorus-32
Solving with the given data:
[tex]A=(1 kg)2^{\frac{-100.1 days}{14.3 days}}[/tex]
[tex]A=0.0078 kg[/tex] This is the remaining amount of phosphorus-32
