A baby goes to sleep at 8 p.m., wakes up after two hours, stays awake for 15 minutes, and then goes back to sleep. If the baby repeats this sleep pattern until she is awakened at 6 a.m., what percent of the time from 8 p.m. to 6 a.m. was the baby asleep?

If the baby repeats this sleep pattern until she is awakened at 6 a.m., what ... We have 10 hours between 8PM and 6AM = 10 * 60 = 600 minutes ... Awake 12:15 - 12:30 ... There are 4 periods of 2 hour sleep and 1 period of 1 hour sleep = 4*2(60) + 1(60) ... So 540/600 = 54/60 = 9/10 = 90% of the time asleep.

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texaschic101 texaschic101 · Answer 2 · 2020-01-23T15:16:56+01:00

Answer:

87.5%

Step-by-step explanation:

I am not sure how to set this up....so I am just gonna try to figure this a different way....without any formula

8 p.m - 10 pm.......awake for 15 minutes

10 pm - 12 am......awake 15 minutes

12 am - 2 am.......awake 15 minutes

2 am to 4 am.....awake 15 minutes

4 am to 6 am....awake 15 minutes

so from 8 pm to 6 am....that is a total of 10 hrs.....and in those 10 hrs, the baby was awake 5(15) = 75 minutes.....change 10 hrs to minutes.....1 hr = 60 min...so 10 hrs = (10 * 60) = 600 minutes

so in 600 minutes, the baby was awake 75 minutes.....that means the baby was asleep (600 - 75) = 525 minutes

525/600 = 0.875 = 87.5% <=== baby was asleep

or maybe this way....for every 2 hrs, the baby was awake 15 minutes....means the baby was asleep (120 - 15) = 105 minutes.

2 / 105 = 10 / x

2x = 1050

x = 1050/2

x = 525 minutes.....so the baby was asleep 525 minutes out of 600 minutes.

525/600 = 0.875 = 87.5%

I am getting the same answer either way