You are provided with a fuel cell that is designed to operate at j = 3 A∕cm2 and P = 1.5 W∕cm2. How much fuel cell active area (in cm2) is required to deliver 2 kW of electrical power? (This is approximately enough to provide power to the average American home.)
(a) 296.3 cm2
(b) 1333.3 cm2
(c) 444.4cm2
(d) 666.6 cm2

Respuesta :

Answer:

correct option is b) 1333.3 cm²

Explanation:

given data    

power P =  1.5 W∕cm²

j   =  3 A∕cm²    

electrical power   =  2 kW

solution          

as given 1.5 W∕cm² power mean 1.5 W  power  operated  by 1  cm²

so here 2 kW i.e here 2000 W power is operated in

2000 W power is operated = [tex]\frac{2000W*1cm^2}{1.5W}[/tex]

= 1333.33 cm²

so correct option is b) 1333.3 cm²