Answer: [tex]7.0\times 10^2kJ[/tex] will be released when 0.25 moles of glucose in a can of soda is metabolized
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion 1 mole of glucose = 2.8 MJ = [tex]2.8\times 10^3kJ[/tex] [tex]1MJ=10^3kJ[/tex]
Thus we can say:
1 mole of glucose on combustion releases = [tex]2.8\times 10^6J[/tex]
Thus 0.25 moles of glucose on combustion releases =[tex]\frac{2.8\times 10^3kJ}{1}\times 0.25=7.0\times 10^2kJ[/tex]
Thus [tex]7.0\times 10^2kJ[/tex] will be released when 0.25 moles of glucose in a can of soda is metabolized
