Respuesta :
Answer:
a. a nontaster girl= 1/8
b. a taster girl= 3/8
c. a taster boy= 3/8
Explanation:
Let's assume that the allele "T" is responsible for the taster phenotype while the recessive allele "t" gives the nontaster phenotype. The taster woman had a nontaster father (tt). Therefore, she is heterozygous dominant (Tt). The taster man had a nontaster daughter (tt) which means that he also has one "t" allele and his genotype is "Tt".
A cross between Tt and Tt would produce progeny in following ratio=
Tt x Tt= 3/4 taster: 1/4 nontaster
The probability of sons and daughters during each reproduction is=
XX x XY= 1/2 XX and 1/2 XY
Therefore,
a. probability of having a nontaster girl= 1/4 x 1/2 = 1/8
b. a taster girl= 3/4 x 1/2 = 3/8
c. a taster boy= 3/4 x 1/2 = 3/8
