Respuesta :
Answer: The number of bottles that will be needed are 6
Explanation:
We are given:
Amount of solution, the intern is asked to prepare = 3 L = 3000 mL (Conversion factor: 1 L = 1000 mL)
Strength of solution needed = 30 % (w/v)
This means that in 100 mL of solution, the solute present is 30 grams
So, in 3000 mL of solution, the solute present will be = [tex]\frac{30}{100}\times 3000=900g[/tex]
Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)
Conversion factor used: 1 ounce = 29.57 mL
So, [tex]8ounce\times \frac{29.57mL}{1ounce}=236.6mL[/tex]
Amount of active ingredient present in 1 bottle = [tex]236.6\times \frac{70}{100}=165.6g[/tex]
To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:
[tex]\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}[/tex]
Putting values in above equation, we get:
[tex]\text{Number of bottles}=\frac{900g}{165.6g}\\\\\text{Number of bottles}=5.43\approx 6[/tex]
Hence, the number of bottles that will be needed are 6
The number of bottles of active ingredients that would be needed will be approximately 6.
1 ounce = 0.0296 liters
8 ounce = 0.0296 x 8
=0.2368 Liters
This means that each stock bottle is 0.2368 liters.
From dilution equation:
Molarity x volume before dilution = molarity x volume after dilution
Before dilution: molarity = 70% w/v, volume = ?
After dilution: molarity = 30% w/v, volume = 3 L
volume before dilution = 30 x 3/70
= 1.286 L
Thus, 1.286 liters of the stock would be needed. Each bottle of the stock is 0.2368 liters. Therefore:
1.286/0.2368
= 5.43
Thus, the number of bottles that would be needed is approximately 6.
More on dilution can be found here: https://brainly.com/question/13844449
