Answer:
(a) 2400N
(b) different
Explanation:
2.5 milliseconds = 0.0025 seconds
a) The momentum of the moving arm-hand of 1.5 kg and at 4m/s speed is the product of the mass and the speed
[tex]p = mv = 1.5 * 4 = 6 kgm/s[/tex]
After the slap, the arm-hand comes to rest, making the change in momentum of 6 - 0 = 6 kgm/s. This change in momentum is due to the impulse generated by the force within t = 0.0025 seconds.
So the average force is:
[tex]F = \frac{\Delta p}{\Delta t} = \frac{6}{0.0025} = 2400 N[/tex]
b) If there are 2 hands clapping together at same speed and mass, their total momentum must be double of that. This makes the average force 2 times as before.
