Answer:
ρ = 800 kg/m³
Explanation:
Let the volume of the sphere = V
and the density of the sphere = ρ
density of water , ρ_w = 1000 Kg/m^3
tension in the string is one-fourth the weight of the sphere.
Tension in the rope ,
[tex]T = \rho V \dfrac{g}{4}[/tex]
for the sphere to in equilibrium
T + Weight = buoyant force
[tex]\rho V\dfrac{g}{4} + \rho V g = \rho_w V g[/tex]
[tex] \dfrac{\rho}{4}+\rho= \rho_w[/tex]
[tex] \dfrac{5\rho}{4}= 1000[/tex]
ρ = 800 kg/m³
density of the sphere is equal to 800 kg/m³
