Answer:
mass of the water removed = 66.67 kg
Step-by-step explanation:
given data
solids is blended with sugar = 10%
obtain final product = 15% product
obtain final product = 15% sugar solids
The initial product is = 200 kg
solution
we get here amount of sugar required that is
amount of sugar required = 200 × [tex]\frac{10}{100}[/tex]
amount of sugar required = 20 kg
and we know total solid = product solids + sugar solids ...............1
and
initial product = final product
so
0.20 × 200kg= 0.30 × mass of the final product
mass of final product = 133.33 kg
but here
final product = 15% product solids and 15% sugar solids
so that amount of product solid = sugar solid
so
mass of the water removed = 200 kg - 133.33 kg
mass of the water removed = 66.67 kg