Answer:
The decomposition of 25.0 g NaHCO₃ produces 6.55 g CO₂
Explanation:
Hi there!
Let´s write the equation:
2NaHCO₃ → Na₂CO₃ + H₂O + CO₂
2 moles of NaHCO₃ produce 1 mol of CO₂
The molar mass of NaHCO₃ is 84.007 g/mol
The molar mass of CO₂ is 44.01 g/mol
2 · 84.007 g NaHCO₃ (2 mol) produce 44.01 g CO₂ (1 mol)
Then 25.0 g NaHCO₃ will produce:
2 · 84.007 g NaHCO₃ ⇒ 44.01 g CO₂
25. 0 g NaHCO₃ ⇒ 25 · 44.01 / 2 · 84.007 = 6.55 g CO₂
The decomposition of 25.0 g NaHCO₃ produces 6.55 g CO₂
