Answer:
The primary current will be 7.2 A.
Explanation:
Given that
Transfer ratio ,TR
[tex]TR=\dfrac{N_1}{N_2}[/tex]
TR= 2.5 :1
[tex]2.5=\dfrac{N_1}{N_2}=\dfrac{V_1}{V_2}=\dfrac{I_2}{I_1}[/tex]
N₁=Number of turns on the primary side of the transformer
N₂=Number of turns on the secondary side of the transformer
I₁=current on the primary side of the transformer
I₂=current on the secondary side of the transformer
We can say that
[tex]2.5=\dfrac{I_2}{I_1}[/tex]
Given that secondary current = I₂
I₂=18 A
Now by putting the values we get
[tex]2.5=\dfrac{18}{I_1}\\I_1=\dfrac{18}{2.5}\\I_1=7.2 A[/tex]
The primary current will be 7.2 A.
