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"If a ball is thrown into the air with a velocity of 44 ft/s, its height in feet t seconds later is given by y = 44t − 16t2. (a) Find the average velocity for the time period beginning when t = 2 and lasting for each of the following. (i) 0.5 seconds ft/s (ii) 0.1 seconds ft/s (iii) 0.05 seconds ft/s (iv) 0.01 seconds ft/s (b) Estimate the instantaneous velocity when t = 2. ft/s"(c) Find the average velocity for the time period beginning whent = 2 and lasting 0.05 second. ft/s(d) Find the average velocity for the time period beginning whent = 2 and lasting 0.01 second. ft/s(e) Estimate the instantaneous velocity when t = 2.

Respuesta :

Answer:

i) -28 ft/s

ii) -21.6 ft/s

iii) -20.8 ft/s

iv) -20.16 ft/s

b)  -20 ft/s

Step-by-step explanation:

if v represents vertical velocity then if the height y is

y = 44*t − 16*t²

and the instant velocity v is the derivative with respect to the time

v= dy/dt = 44*(1) - 16*(2*t) = 44- 32*t

while the average velocity is va= (y-y₀)/(t-t₀)

where t₀ = 2 and y₀=y(t₀) =  44*2 − 16*2² = 24

then

va= (y-y₀)/(t-t₀) = (44*t − 16*t² -  24)/(t-2)

for

i) t= 0.5s + 2 s= 2.5 s

va = (44* 2.5  − 16* 2.5 ² -  24)/( 2.5 -2) = -28 ft/s

ii) t= 0.1s + 2 s= 2.1 s

va = (44* 2.1  − 16* 2.1 ² -  24)/( 2.1 -2) = -21.6 ft/s

iii) t= 0.05 s + 2 s= 2.05 s

va = (44* 2.05  − 16* 2.05 ² -  24)/( 2.05 -2) = -20.8 ft/s

iv) t= 0.01s + 2 s= 2.01 s

va = (44* 2.01  − 16* 2.01 ² -  24)/( 2.01 -2) = -20.16 ft/s

b) the instantaneous velocity when t=2

v (t=2) =  44- 32*(2) = -20 ft/s

Answer:

i) The first  -28 ft/s

ii) Then second -21.6 ft/s

iii) Thirds one is -20.8 ft/s

iv) Then  -20.16 ft/s

b)  -20 ft/s

Step-by-step explanation:

  • When if v represents vertical velocity then if the height y is
  • then y = 44*t − 16*t²
  • After that and the instant velocity v is the derivative with respect to the time
  • Now v= dy/dt = 44*(1) - 16*(2*t) = 44- 32*t
  • Also that while the average velocity is va= (y-y₀)/(t-t₀)
  • After that where t₀ = 2 and y₀=y(t₀) =  44*2 − 16*2² = 24
  • then va= (y-y₀)/(t-t₀) = (44*t − 16*t² -  24)/(t-2)
  • for (i) t= 0.5s + 2 s= 2.5 s
  • Now va = (44* 2.5  − 16* 2.5 ² - 24)/( 2.5 -2) = -28 ft/s
  • Next (ii) t= 0.1s + 2 s= 2.1 s
  • After that va = (44* 2.1  − 16* 2.1 ² - 24)/( 2.1 -2) = -21.6 ft/s
  • Now (iii) t= 0.05 s + 2 s= 2.05 s
  • Then va = (44* 2.05  − 16* 2.05 ² -  24)/( 2.05 -2) = -20.8 ft/s
  • iv) t= 0.01s + 2 s= 2.01 s
  • After that va = (44* 2.01  − 16* 2.01 ² -  24)/( 2.01 -2) = -20.16 ft/s
  • When b) the instantaneous velocity then t=2
  • Now v (t=2) = 44- 32*(2) = -20 ft/s

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