Answer:
A
Step-by-step explanation:
Consider triangle OAM and OBM. In these triangles,
- OA is congruent to OB as radii of one circle;
- AM is congruent to BM as radii of two congruent circles;
- OM is congruent to OM by reflexive property (this side is common).
Thus, triangles OAM and OBM are congruent by SSS postulate.
Congruent triangles have congruent corresponding parts, so
[tex]\angle AOM\cong \angle BOM[/tex]
Hence, OM is angle AOB bisector.
