Respuesta :
Answer:
[tex]1 : 315[/tex]
Explanation:
As we know that
one quart is equal to [tex]946.3[/tex] mls
one table spoon is equal to [tex]15[/tex] mls
Therefore, two table spoon is equal to
[tex]2 * 15 = 30[/tex] mls
[tex]Q_1 * C_1 = Q_2 * C_2[/tex]
Here,
[tex]Q_1[/tex] & [tex]Q_2[/tex] represents the volume
[tex]C_1[/tex] & [tex]C_2[/tex] represents the concentration
Substituting the given values in above equation, we get -
[tex]30 * 10[/tex]% [tex]= 946.3 * X[/tex]%
[tex]X[/tex]% [tex]= \frac{30 * 10}{946.3}[/tex]
[tex]X[/tex]% [tex]= 0.317[/tex] %
[tex]0.317[/tex] % [tex]= 100 : 0.317[/tex]
[tex]1 : 315[/tex]
Following are the calculation to the ratio strength of the dilution:
Initial concentration, [tex]C_1 = 30\% = 0.30[/tex]
Initial volume, [tex]V_1 = 2 \times 15 = 30 \ mL \ \text{(2 tablespoonfuls)}[/tex]
Using filtered water, dilute this solution to 1 quart.
Let the diluted solution have a strength of [tex]C_2[/tex]:
[tex]\because 1\ quart = 946.35 \ mL \\\\ \therefore V_2 = 946.35\ mL \\\\[/tex]
Now,
[tex]\to V_1C_1 = V_2C_2\\\\ \to (30) (0.30) = (946.35)C_2\\\\\to C_2= \frac{(30)(0.30)}{946.35}[/tex]
[tex]=\frac{9}{ 946.35}\\\\=\frac{1}{105.15}\\\\= 1 : 105.15 \approx 1: 105[/tex]
Therefore, the strength ratio of the diluted solution is "1: 105".
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