Answer:
16 KJ or 16,720 J energy has gained by the water.
Explanation:
Given data:
Mass of water = m = 100 g
Temperature difference = ΔT= (60 - 20)∘C
specific heat of water 1 calorie = c = 4.18 J
To find:
Heat absorbed by water = q=?
Formula:
q = m . c . ΔT
Solution:
q = (100 g) x (4.18J/g ∘C) x (60 - 20)∘C
= 16,720 J
