Which of these strategies would eliminate a variable in the system of equations?
10x+4y=-2
5x-2y=2

Answer:
Option A: Multiply the top equation by [tex]$ \frac{\textbf{1}}{\textbf{2}} $[/tex], then add the equations.
Step-by-step explanation:
OPTION A:
When we multiply the top equation by [tex]$ \frac{1}{2} $[/tex] we get:
[tex]$ \frac{1}{2}10x + \frac{1}{2}4y = \frac{1}{2}(-2) $[/tex]
[tex]$ = 5x + 2y = -1 $[/tex]
Now, we add the second equation to this, we get:
5x + 2y + 5x - 2y = -1 + 2
[tex]$ \implies 10x = 1 $[/tex]
The 'y' variable is eliminated.
OPTION B: Note that multiplying the second equation by 2 would result in:
10x - 4y = 4. To eliminate 'y' we should add this equation to the top equation not subtract it. So, this option is wrong.
OPTION C:
Adding the equations also will result in a equation of two variables, viz:
15x + 2y = 0 which does not eliminate any variable at all.
So, OPTION C is also wrong.
Hence, OPTION A is the answer.
Answer:
A AND B IS THE CORRECT ANSWER
Step-by-step explanation:
I JUST TOOK THE TEST :)