Answer:
The first operation performed when evaluating the given expression [tex]5+(\frac{9x-3}{2})[/tex] for x=5 is given below :
Step 1: Put x=5 in the above given expression we get
[tex]5+(\frac{9(5)-3}{2})[/tex]
Step-by-step explanation:
Given equation is [tex]5+(\frac{9x-3}{2})[/tex] for x=5
To find the first operation performed when evaluating the given expression [tex]5+(\frac{9x-3}{2})[/tex] for x=5
[tex]5+(\frac{9x-3}{2})[/tex]
Step 1: Put x=5 in the above expression we get
[tex]5+(\frac{9(5)-3}{2})[/tex]
[tex]=5+(\frac{45-3}{2})[/tex]
[tex]=5+(\frac{42}{2})[/tex]
[tex]=5+21[/tex]
[tex]=26[/tex]
Therefore [tex]5+(\frac{9x-3}{2})[/tex] for x=5 is 26
Therefore [tex]5+(\frac{9x-3}{2})=26[/tex] for x=5
