Answer:
The Cost of yellow shirts is $15 and the cost of purple shirt is $ 60
Step-by-step explanation:
Let cost of one yellow shirt be x
and the cost of one purple shirt be y
On Monday
5x + 7y = 165--------------------(1)
On Tuesday
4x + 11y = 213----------------------(2)
To solve (1) and (2)
multiplying eq(1) with 4
20x + 28y = 660--------------------(3)
multiplying eq(2) with 5
20x + 55y = 1056-------------------(4)
Subtracting (3) from (4)
20x + 55y = 1056
20x + 28y = 660
(-)
-----------------------------------
0x +27y = 405
-----------------------------------
[tex]y = \frac{405}{27}[/tex]
y = 15
Substituting y value in eq(1)
5x + 7(15) = 165
5x + 105 =405
5x =405 -105
5x =300
x = \frac{300}{5}
x =60
Answer:
Each purple shirt costs $12
Each yellow shirt costs $15
Step-by-step explanation:
Let's call:
x: purple shirt price (in dollars per shirt)
y: yellow shirt price (in dollars per shirt)
On Monday, the store collected $165 selling 5 purple shirts and 7 yellow shirts. That is:
5*x + 7*y = 165 (eq. 1)
On Tuesday, the store collected $213 selling 4 purple shirts and 11 yellow shirts. That is:
4*x+11*y = 213 (eq. 2)
We can isolate y in equation 1, as follows:
7*y = 165 - 5*x
y = 165/7 - 5/7*x
and replace it in equation 2:
4*x+11*(165/7 - 5/7*x) = 213
4*x+ 1815/7 - 55/7*x = 213
-27/7*x = 213 - 1815/7
-27/7*x = -324/7
x = -324/-27 = 12
Then:
y = 165/7 - 5/7*12 = 15
If we graph the system of equations made by equations 1 and 2, we get the figure attached. The intersection of the two lines is the solution of the system.
