Respuesta :
The value of [tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex] [tex]=\dfrac{8}{7}[/tex]
Step-by-step explanation:
We have,
[tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex]
To find, the value of [tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex] = ?
∴ [tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex]
[tex]=\dfrac{4}{5}\times \dfrac{6}{7} +\dfrac{2}{7}.\dfrac{8}{5}[/tex]
[tex]=\dfrac{24}{35} +\dfrac{16}{35}[/tex]
Taking LCM of denominator, we get
[tex]=\dfrac{24+16}{35}[/tex]
[tex]=\dfrac{40}{35}[/tex]
Dividing numerator and denominator by 5, we get
[tex]=\dfrac{8}{7}[/tex]
∴ The value of [tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex] [tex]=\dfrac{8}{7}[/tex]
Hence, the value of [tex]\dfrac{4}{5}[/tex] ÷ [tex]\dfrac{7}{6}[/tex] + [tex]\dfrac{2}{7}.2\dfrac{1}{5}[/tex] is equal to [tex]\dfrac{8}{7} .[/tex]
