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A 10- kilogram block is pushed across a horizontal surface with a horizontal force of 20 N against a friction force of 10 N. The acceleration of the block is_______.

Respuesta :

lublana

Answer:

[tex]1m/s^2[/tex]

Explanation:

Mass of block=10 kg

Applied horizontal force =F=20 N

Friction force=f=10 N

We have to find the acceleration of block.

Net force=Applied horizontal force-friction force

[tex]ma=F-f[/tex]

Where F= Horizontal force

f=Friction force

m=Mass of object

a=Acceleration of object

[tex]10a=20-10=10[/tex]

[tex]a=\frac{10}{10}=1 m/s^2[/tex]

Hence, the acceleration of the block=[tex]1m/s^2[/tex]

asuwafohjames

The acceleration of the block is 1 m/s².

What is acceleration?

Acceleration can be defined as the rate of change of velocity

To calculate the acceleration of the block, we use the formula below.

Formula:

  • ma = F-F'............... Equation 1

Where:

  • m = mass of the block
  • a = acceleration of the block
  • F = horizontal force applied to the block
  • F' = friction force.

Make a the subject of the equation

  • a = (F-F')/m............. Equation 2

From the question,

Given:

  • F = 20 N
  • F' = 10 N
  • m = 10 kg

Substitute these values into equation 2

  • a = (20-10)/10
  • a = 10/10
  • a = 1 m/s²

Hence, The acceleration of the block is 1 m/s².

Learn more about acceleration here: https://brainly.com/question/12043464