Answer:
The answer to your question is width = 8ab³
Step-by-step explanation:
Data
Area = 32a³b⁴ u²
length = 4a²b u
Formula
Area of a rectangle = width x length
Solve for width
width = [tex]\frac{Area}{length}[/tex]
Substitution
width = [tex]\frac{32a^{3}b^{4}}{4a^{2}b}[/tex]
Simplify using rules of exponents, just remember that in a division we subtract the exponents and divide the coefficients normally.
width = 8 a²b³
Answer:
Step-by-step explanation: 32a^3 is -8 < a < - 8 axis interceptions 32a^3 vertical asymphotes None Extreme points of a32a^3 0,0
