Answer:
Volume of lithium atom is found to be 1.47 X 10⁻²⁹ m³
Explanation:
Let us consider the volume of atom as a sphere (but it is little complex than that). This volume is mathematically expressed as,
[tex]V=\frac{4}{3}\pi R^{3}[/tex]----------------------------------------------------------------------------------------(Eq. 1)
Here, R is the radius of lithium atom. The radius is given in picometers, so firstly let us convert it into meters
[tex]R=(152pm )(1X10^{-12}\frac{m}{pm})[/tex]
[tex]R = 1.52 X 10^{-10}m[/tex]
placing this value in Eq.1 the required result is achieved
[tex]V=\frac{4}{3}\pi {1.52X10^{-10}}^{3}[/tex]
V= 1.47 X 10⁻²⁹ m³
The volume of the lithium atom is [tex]1.47 \times 10^{-29} \ m^3[/tex].
The given parameters:
The volume of the lithium atom is calculated from the volume of a sphere as follows;
[tex]V = \frac{4}{3} \pi r^3[/tex]
where;
[tex]\\\\V = \frac{4}{3} \times \pi \times (152 \times 10^{-12})^3\\\\V = 1.47 \times 10^{-29} \ m^3[/tex]
Thus, the volume of the lithium atom is [tex]1.47 \times 10^{-29} \ m^3[/tex]
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