Answer: The mass of cryolite produced is 65.06 kg
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of aluminium oxide = 15.8 kg = 15800 g (Conversion factor: 1 kg = 1000 g)
Molar mass of aluminium oxide = 102 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of aluminium oxide}=\frac{15800g}{102g/mol}=154.9mol[/tex]
For the given chemical reaction:
[tex]Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)[/tex]
As all the reactants are getting completely utilized. So, the amount of product can be determined by any 1 of the reactant.
By Stoichiometry of the reaction:
1 mole of aluminium oxide produces 2 moles of cryolite
So, 154.9 moles of aluminium oxide produces = [tex]\frac{2}{1}\times 154.9=309.8mol[/tex] of cryolite
Now, calculating the mass of cryolite by using equation 1, we get:
Moles of cryolite = 309.8 moles
Molar mass of cryolite = 210 g/mol
Putting values in equation 1, we get:
[tex]309.8mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(309.8mol\times 210g/mol)=65058g=65.06kg[/tex]
Hence, the mass of cryolite produced is 65.06 kg