The equation of line passing through given points is:
[tex]y = -\frac{1}{4}x+\frac{7}{4}[/tex]
Step-by-step explanation:
Given points are:
(x1,y1) = (-1,2)
(x2,y2) = (3,1)
Slope-intercept form of equation is:
[tex]y=mx+b[/tex]
First of all, we have to find the slope
[tex]m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{1-2}{3-(-1)}\\m=\frac{-1}{3+1}\\m = -\frac{1}{4}[/tex]
Putting the value of slope
[tex]y = -\frac{1}{4}x+b[/tex]
To find the value of b, putting a (3,1) in the equation
[tex]1 = -\frac{1}{4} (3)+b\\1 = -\frac{3}{4}+b\\b = 1+\frac{3}{4}\\b = \frac{4+3}{4}\\b = \frac{7}{4}[/tex]
Putting the value of b
[tex]y = -\frac{1}{4}x+\frac{7}{4}[/tex]
Keywords: Equation of line, slope
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Answer:
Step-by-step explanation:
The answer is x+4y=7
The choices are:
a. 4x-y= -6
b. x+4y= 7
c. x-4y= -9
d. 4x+y= 2
