Respuesta :

Answer:

33.83 g

Explanation:

Data given:

Amount of Oxygen = 14.5 grams

Grams of Iron (Fe) = ?

Solution:

To solve this problem first we will look for the reaction that iron react with oxygen

Reaction:

           4Fe + 3O₂ --------> 2Fe₂O₃

Now if we look at the reaction

          4Fe     +     3O₂     -------->   2Fe₂O₃

          4 mol        3 mol

Now convert moles to mass

Then

Molar mass of iron = 56 g/mol

Molar mass of O₂ = 2(16) = 32 g/mol

So,

          4Fe                  +               3O₂            ------------>   2Fe₂O₃

     4 mol (56 g/mol)              3 mol (32 g/mol)

             224 g                               96 g

So if we look at the reaction; 224 g of iron (Fe) react with 96 g of oxygen (O₂) in a this reaction, then how many grams of iron (Fe) will react with 14.5 grmoles of iron (Fe)

For this apply unity formula

               224 g  of iron (Fe) ≅ 96 g of oxygen (O₂)

                X of iron (Fe) ≅ 14.5 g of oxygen (O₂)

By Doing cross multiplication

              X g of iron (Fe) = 224 g x 14.5 g / 96 g

             X g of iron (Fe) = 33.83 g

33.83 g of iron (Fe) will react with 14.5 g of oxygen (O₂)

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