Answer:
[tex]4(x+3.5)^{2}=0[/tex]
Step-by-step explanation:
we have
[tex]4x^{2}+28x+49=0[/tex]
step 1
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex](4x^{2}+28x)=-49[/tex]
step 2
Factor the leading coefficient
[tex]4(x^{2}+7x)=-49[/tex]
step 3
Complete the square. Remember to balance the equation by adding the same constants to each side
[tex]4(x^{2}+7x+3.5^2)=-49+(3.5^2)(4)[/tex]
[tex]4(x^{2}+7x+12.25)=0[/tex]
step 4
Rewrite as perfect squares
[tex]4(x+3.5)^{2}=0[/tex]
