At standard temperature and pressure, a 0.50 mol sample of H2 gas and a separate 1.0 mol sample of O2 gas have the same A. average molecular knetic energyB. average molecular speedC. volumeD. effusion rateE. density

Respuesta :

Answer:

The correct answer is option A.

Explanation:

The average kinetic energy of the gas particle only depends upon the temperature of the gas.

The formula for average kinetic energy is:

[tex]K.E=\frac{3}{2}kT[/tex]

where,

k = Boltzmann’s constant = [tex]1.38\times 10^{-23}J/K[/tex]

T = temperature

So, at standard temperature and pressure 0.50 moles of hydrogen and 1.0 mole of oxygen sample will have same value of average kinetic energy.

Where as in other option enlisted in question , molar masses of both gases will be involved which will give different answers for both the gases.

This question involves the concepts of the average kinetic energy of the molecules of a gas and temperature.

The gases will have the same "A. average molecular kinetic energy".

The average kinetic energy of gas molecules is given by the following formula:

[tex]K.E = \frac{3}{2}KT[/tex]

where,

K.E = average kinetic energy

K = Boltzmann constant

T = absolute temperature

Hence, the average kinetic energy depends upon the absolute temperature only. Since the temperature is the same for both gases. Hence, their average kinetic energy will also be the same.

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