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The only swimming pool at the El Cheapo Motel is outdoors. It is 5.0 m wide and 12.0 m long. If the weekly evaporation is 2.35 in., how many gallons of water must be added to the pool if it does not rain?

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pedrocarratore

Answer:

946.10 gallons per week

Step-by-step explanation:

1 cm = 0.393701 inch

Width = 5.0m = 196.85 inch

Length = 12.0 m = 472.44 inch

The volume evaporated weekly is given by:

[tex]V = L*W*2.35 = 196.85*472.33*2.35\\V=218,550.12\ in^3[/tex]

Converting to gallons:

[tex]1\ gal = 231\ in^3\\V=\frac{218,550.12}{231}\\V= 946.10\ gal[/tex]

946.10 gallons of water must be added to the pool each week.

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