Jerry started doing sit-ups every day. The first day he did 13 sit-ups. Every day after that he did 2 more sit-ups than he had done the previous day. Today Jerry did 29 sit-ups. Write an equation that could be solved to find the number of days Jerry has been doing sit-ups, not counting the first day. Let n represent the number of days.

An equation that can help Jerry to find the number of days he has been doing sit-ups is given by

Respuesta :

Answer:

An equation that can help Jerry to find the number of days he has been doing sit-ups is   [tex]\frac{a_{n} -13}{2} +1 = n[/tex]

Step-by-step explanation:

First day = 13

Second day =  first day + 2 = 13 +2 =15

Third day  =  second day + 2 =  17

Fourth day = Third day +2  = 19

So,

13 , 15 , 17, 19, 21, 23 ...........

The common difference is 2

By using arithmetic series

[tex]a_{n} = 13 + (n-1)d[/tex]

where

[tex]a_n[/tex] is the number of sit-ups done on the nth day

n is  number of the days

d is the difference

Now

[tex]a_{n} = 13 + (n-1)(2)[/tex]

[tex]a_{n} -13 = (n-1)(2)[/tex]

[tex]\frac{a_{n} -13}{2} = (n-1)[/tex]

[tex]\frac{a_{n} -13}{2} +1 = n[/tex]