Answer:
[tex]F=0.0231\ N[/tex]
Explanation:
Electrostatic Force
When two point charges [tex]q_1[/tex] and [tex]q_2[/tex] are placed at a distance d, they exert a force to each other whose magnitude can be computed by the Coulomb's formula
[tex]\displaystyle F=\frac{k\ q_1\ q_2}{d^2}[/tex]
Where k is the constant of proportionality
[tex]k=9.10^9\ Nw.m^2/c^2[/tex]
The information provided is
[tex]d=10^{-13}\ m[/tex]
[tex]q_1=q_2=+ 1.602 x 10^{-19}\ C[/tex]
Computing the Coloumb force between them
[tex]\displaystyle F=\frac{9x10^9\ 1.602 x 10^{-19} \ 1.602 x 10^{-19} }{(10^{-13})^2}[/tex]
[tex]\boxed{F=0.0231\ N}[/tex]
