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A truck driver has a shipment of apples to deliver to a destination 550 miles away. The trip usually takes him 10.0 hours. Today he finds himself daydreaming and realizes 120 miles into his trip that that he is running 30.0 minutes later than his usual pace at this point. If the driver still wishes to complete the trip in 10.0 hours, how fast must he drive for the rest of the trip? (In all questions, you may assume that the truck moves with a constant speed.)

At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time? Express your answer using three significant figures.

Respuesta :

ikuemuyaolusegun

Answer: He must drive at 58.8mi/hr

{3 significant figure}

Explanation: The original speed of the car to complete the journey normally is = 550mile/10hr

= 55mi/hr

The normal time to cover 120 mile with that speed is

t = distance/speed

= 120/55

=2hr, 0.18*60=11mins

= 2hr11mins.

But the driver found out he was 30mins behind at this distance, so he spent

2hr 11min +30min= 2hr41mins

For him to meet up the original schedule time 10hrs, he has

(10-2.41)hrs = 7hr19mins to cover the remaining distance of

{550-120}=430mile.

First, 7hr19mins= {7*(19/60)}hr

= {439/60}hr

Now let's find the speed at which the driver must move for him to cover for his initial delay

Speed= distance/time

= 430/{439/60}

This is same as writing

Speed = 430/439/60

Using the law of reciprocal,

Speed = (430*60)/439

= 25800/439

= 58.7699mi/hr

But we were asked to leave our answer in 3 significant figure. Therefore,

Speed = 58.8mi/hr

At a speed of 58.8mi/hr must he drive for the remainder of the trip to complete the trip in the usual amount of time.

What is velocity?

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The time it takes to go 120 miles at that speed in normal conditions is;

[tex]\rm t = \frac{d}{v} \\\\ t =\frac{120}{55} \\\\ t= 2 hour \ 11 minute[/tex]

However, the driver was 30 minutes behind schedule at this distance, so the time the has to spend is;

T== 2hr 11 min +30 min

T= 2hr 41 mins

He has to fulfill the initial planned moment of 10 hours. The time to cover the remaining distance;

T'=(10-2.41)

T' = 7hr19mins

The remaining distance will be ;

S={550-120}

S=430mile.

The speed is to be maintained the following distance on the time;

[tex]\rm V'=\frac{430}{(\frac{439}{60} )} \\\\V'=58.7699 \ miles / hour[/tex]

The speed must he drive for the remainder of the trip to complete the trip in the usual amount of time will be 58.5 mile/hr.

To learn more about the velocity refer to the link;

https://brainly.com/question/862972

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