Starting from a single individual, what is the size of a population of bacteria that reproduce by binary fission every 20 minutes at the end of a 2-hour time period? (Assume unlimited resources and no mortality.)
A) 6
B) 18
C) 128
D) 512
E) 1,024

Respuesta :

Answer:

 C) 128

Explanation:

In binary fission each bacterial cell will divide into two parts.

1. Since the bacteria divides divides after every 20 min , We have to find the number of division in two hours two hour(2x60=120 min) which will be;

120÷20=6

It will undergo 6 divisions.

2. To calculate the number of bacteria at the end of 2 hours

Bacteria in the beginning x 2∧ Number of division

1× 2∧6= 128 Bacteria  

Oseni

The size of a population of bacteria that reproduce by binary fission every 20 minutes starting from a single individual and lasting for 2 hours would be 64.

There are 120 minutes in a 2 hour period.

Starting at 0 minutes with 1 individual

After 20 minutes, there will be 2 individuals

After 40 minutes, there will be 4 individuals

after 60 minutes, 8 individuals

After 80 minutes, 16 individuals

After 100 minutes, 32 individuals

After 120 minutes. 64 individuals

More on bacterial division can be found here: https://brainly.com/question/10046744