Answer:
T = 26.16 [N]
Step-by-step explanation:
We have a mass of 2 kg and a horizontal clothesline tied between two poles 10 meters apart. middle point is 5 meters apart of any of the two poles
Mass of 2 kg means P = 2 kg * g ⇒ P = 2 kg* 9.8 m/sec
P = 19.6 [N]
In a free body diagram is easy to see that we will have a force P = 19.6 [N] acting downwards and two equals tension acting through each half of the clotheslines.
As the clothesline sags, an angle θ with the horizontal line passing at body level, such as tan θ = 2/5 tan θ = 0.4 then from tables we get
θ = 22 ⁰
sin 22 ⁰ = 0.3746
As for equilibrium
∑ Fy = 0
2 Tx = 2 T sin 22⁰ = P
2T * 0,3746 = 19.6
T = 26.16 [N]
