Answer:
The gauge pressure of gas is 112.5 KPa
The absolute pressure of gas is 216.5 KPa
Explanation:
Since, the piston is at rest. Hence, the gauge pressure of the gas will be equal to the pressure exerted by the weight of the cylinder.
Gauge Pressure of Gas = (Weight of Piston)/(Cross sectional are of piston)
Gauge Pressure of Gas = mg/Area
We have,
mass = m = 6.3 kg
g = 9.8 m/s²
Area = 550 mm² = 5.5 x 10^-4 m²
Gauge Pressure of Gas = (6.3 kg)(9.8 m/s²)/(5.5 x 10^-4 m²)
Gauge Pressure of Gas = 112.25 x 10^3 Pa = 112.5 KPa
Now, for absolute pressure:
Absolute Pressure of Gas = Gauge Pressure of Gas + Atmospheric Pressure
Absolute Pressure of Gas = 112.5 KPa + 104 KPa
Absolute Pressure of Gas = 216.5 KPa
The gauge pressure of gas in the cylinder is 1.123 x 10⁵ Pa.
The absolute pressure of the gas in the cylinder is 2.163 x 10⁵ Pa.
The given parameters:
The gauge pressure of gas in the cylinder is calculated as follows;
[tex]P_g = \frac{F }{A} \\\\P_g = \frac{mg}{ A} \\\\P_g = \frac{6.3 \times 9.8}{550 \times 10^{-6} }\\\\P_g = 1.123 \times 10^5 \ Pa[/tex]
The absolute pressure of the gas in the cylinder is calculated as follows;
[tex]P_a = P_g + P_{atm}\\\\P_a = 1.123\times 10^5 \ Pa \ \ + \ 1.04 \times 10^5 \ Pa\\\\P_a =2.163\times 10^5 \ Pa[/tex]
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