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An electrical engineer wants to build an electrical circuit with a 3-volt battery connected in series to a light bulb with a resistance of 6 ohms. How much current will be flowing through the light bulb if this circuit is built?

Respuesta :

Answer:

0.5A

Explanation:

GIVEN THAT:

V = 3 V

R =6 ohms

V=IR

I =V/R

I = 3/6 =0.5 A

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