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What is the probability that the first offspring from the cross listed below will show the dominant phenotype for all loci? (type as a decimal and round to 5 decimal places)a. AA bb
b. Dd ee x
c. Aa
d. BB dd
e. Ee

Respuesta :

namordu

Answer:

0.25000

Explanation:

There is an error in the way the question is written, the cross to analyze is:

AAbbDdee x AaBBddEe

If the genes assort independently, we can predict separately for each gene the proportion of the offspring that will have the dominant alleles using Mendel's law of segregation.

AA x Aa

1/2 AA

1/2 Aa

Phenotype: all A

bb x BB

1 Bb

Phenotype: all B

Dd x dd

1/2 Dd

1/2 dd

Phenotype: 1/2 D, 1/2 d

ee x Ee

1/2 Ee

1/2 ee

Phenotype: 1/2 E, 1/2 e

Genes are independent, so the probability of having all dominant phenotype offspring (A_B_D_E_) can be calculated by multiplying for each gene the probabilities of having at least one dominant allele in the offspring:

1 (A_) × 1 (B_) × 1/2 (D_) × 1/2 (E_) = 1/4 = 0.25

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